Monday, Congressman Robert Aderholt (R-Haleyville) announced the hiring of Alex Vanderford as his new campaign manager to organize his 2020 re-election campaign.
“I am excited to announce that Alex Vanderford will be joining our team,” Aderholt announced in a statement. “Alex has a wealth of campaign experience and he shares my vision of reigniting the economy after this pandemic, bringing jobs back from China to America, expanding broadband to all rural areas, and protecting the unborn. I know Alex will work tirelessly to show the voters how much progress we’ve made, but also how we can make even more progress in the future.”
In 2018, Democrats won control of the U.S. House of Representatives for the first time since 2010.
“This is a pivotal election,” Aderholt said. “Speaker Pelosi wants to consolidate her control of Congress and defeat President Trump. I will be working closely with the President to make sure that doesn’t happen.”
The Fourth Congressional District was the most Republican congressional district in the entire country in 2016 and Donald J. Trump (R) remains very popular here.
“I take pride in the fact that President Trump received a higher percentage of the vote in the 4th Congressional District than any congressional district in the nation,” Aderholt stated. “During the past four years, I have formed a personal relationship with President Trump, and we have fought side by side for rural America.”
Alex Vanderford was most recently worked the North Alabama field director for Congressman Bradley Byrne’s (R-Montrose) failed Senate Campaign. He has also worked as the Grassroots Coordinator/Coalitions Director for Republican Marsha Blackburn’s successful Senate campaign in Tennessee.
Alex is a native of Muscle Shoals in Colbert County in the 4th District and is a graduate of Martin Methodist College in Pulaski, Tennessee.
Robert Aderholt is serving in his twelfth term representing Alabama in the U.S. House of Representatives. Aderholt is being challenged by Rick Neighbors in the November general election.
